Everybody enjoys the smell and taste the freshly-baked bread. The is light and also fluffy together a result of the action of yeast ~ above sugar. The yeast counter the street to carbon dioxide, which in ~ high temperatures causes the dough to expand. The end an outcome is an enjoyable treat, especially when spanned with melted butter.

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## Charles"s Law

French physicist Jacques Charles (1746-1823) learned the impact of temperature top top the volume of a gas at continuous pressure. Charles"s Law claims that the volume the a offered mass of gas varies directly with the absolute temperature the the gas as soon as pressure is retained constant. The absolute temperature is temperature measured with the Kelvin scale. The Kelvin scale must be used since zero top top the Kelvin scale synchronizes to a finish stopof molecular motion.

Figure (PageIndex1): as a container of limit gas is heated, the molecules increase in kinetic energy and also push the movable piston outward, result in rise in volume.

Mathematically, the direct relationship that Charles"s Law can be represented by the complying with equation:

As with Boyle"s Law, (k) is continuous only because that a given gas sample. The table listed below shows temperature and volume data for a set amount the gas in ~ a continuous pressure. The 3rd column is the consistent for this specific data set and is always equal come the volume separated by the Kelvin temperature.

Temperature (left( extK ight))Volume (left( extmL ight))(fracVT = k) (left( frac extmL extK ight)) Table (PageIndex1): Temperature-Volume Data
50 20 0.40
100 40 0.40
150 60 0.40
200 80 0.40
300 120 0.40
500 200 0.40
1000 400 0.40

When this data is graphed, the result is a directly line, indicative that a straight relationship, presented in the number below.

Given:

Given:T1 = -27oC and also V1 = 34.8 L

V2 = 25.0 L

Find: T2 = ? K

List other well-known quantities.

K = -27oC + 273

Plan the problem.

1. Transform the early temperature come Kelvin

2. Rearrange the equation algebraically to settle for (T_2).

Cancel units and also calculate.

1. −67°C + 273 = 206 K

2. Substitute the recognized quantities right into the equation and also solve.

Think around your result. This is additionally equal to −125°C. Together temperature decreases, volume decreases—which it does in this example.

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## Summary

Charles’s regulation relates the volume and also temperature the a gasat consistent pressure and also amount.