Obviously, to calculate the volume/space inhabited by a mole of (an ideal) gas, you"ll have to specify temperature (\$T\$) and also pressure (\$P\$), find the gas constant (\$R\$) value through the ideal units and plug them every in the best gas equation \$\$PV = nRT.\$\$

The problem? It seems to be some kind of typical "wisdom" all over the Internet, the one mole that gas occupies \$22.4\$ liters that space. But the standard conditions (STP, NTP, or SATP) mentioned absence consistency over multiple sites/books. Typical claims: A mole that gas occupies,

\$pu22.4 L\$ in ~ STP\$pu22.4 L\$ at NTP\$pu22.4 L\$ in ~ SATP\$pu22.4 L\$ in ~ both STP and NTP

Even Chem.SE is rife with the "fact" the a mole of right gas rectal \$pu22.4 L\$, or some extension thereof.

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Being so completely frustrated through this situation, I chose to calculation the volumes occupied by a mole of right gas (based on the best gas equation) because that each that the three standard conditions; namely: standard Temperature and also Pressure (STP), regular Temperature and also Pressure (NTP) and Standard approximately Temperature and also Pressure (SATP).

Knowing that,

STP: \$pu0 ^circ C\$ and also \$pu1 bar\$NTP: \$pu20 ^circ C\$ and also \$pu1 atm\$SATP: \$pu25 ^circ C\$ and also \$pu1 bar\$

And using the equation, \$\$V = frac nRTP,\$\$where \$n = pu1 mol\$, by default (since we"re talking around one mole of gas).

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I"ll draw proper values that the gas constant \$R\$ from this Wikipedia table:

The volume lived in by a mole of gas should be:

At STPeginalignT &= pu273.0 K,&P &= pu1 bar,&R &= pu8.3144598 imes 10^-2 together bar K^-1 mol^-1.endalignPlugging in all the values, I gained \$\$V = pu22.698475 L,\$\$ which to a reasonable approximation, gives\$\$V = pu22.7 L.\$\$

At NTPeginalignT &= pu293.0 K,&P &= pu1 atm,&R &= pu8.2057338 imes 10^-2 together atm K^-1 mol^-1.endalignPlugging in every the values, I gained \$\$V = pu24.04280003 L,\$\$ which come a reasonable approximation, provides \$\$V = pu24 L.\$\$

At SATPeginalignT &= pu298.0 K,&P &= pu1 bar,&R &= pu8.3144598 imes 10^-2 together bar K^-1 mol^-1.endalignPlugging in every the values, I got \$\$V = pu24.7770902 L,\$\$ which come a reasonable approximation, gives \$\$V = pu24.8 L.\$\$

Nowhere go the wonder "\$pu22.4 L\$" figure in the three cases I"ve analyzed appear. Since I"ve viewed the "one mole rectal \$pu22.4 L\$ in ~ STP/NTP" dictum so many times, I"m wondering if I"ve let go something.

My question(s):

Did ns screw up with my calculations?(If ns didn"t screw up) Why is it that the "one mole rectal \$pu22.4 L\$" idea is so widespread, in spite of not gift close (enough) to the worths that ns obtained?