Multiples of 6 are the products of 6 and natural numbers. In other words, a multiple of 6 is a number that can be divided by 6 and leaves the remainder zero. Interestingly, multiples of 6 have a difference of 6 between each other. In this mini-lesson, we will calculate the multiples of 6 and learn interesting facts about these multiples. In this mini-lesson, let"s learn more about multiples of 6 in the tabular form with examples.

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First five multiples of 6: 6, 12, 18, 24, 30Prime factorization of 6: 2 x 3
 1 What Are the Multiples of 6? 2 First 20 Multiples of 6 3 Important Notes 4 FAQs on Multiples of 6

The product of 6 with any number is a multiple of 6.

6×1 = 6

6×2 = 12

6×3 = 18

We get successive multiples of 6 by skip counting.

If we skip count 128 times by 6, we will get the 128th multiple of 6. i.e., 128×6 = 768.

We obtain the first 20 multiples of 6 by finding the product of 6 and the first 20 natural numbers.

ProductMultiples
6 × 16
6 × 212
6 × 318
6 × 424
6 × 530
6 × 636
6 × 742
6 × 848
6 × 954
6 × 1060
6 × 1166
6 × 1272
6 × 1378
6 × 1484
6 × 1590
6 × 1696
6 × 17102
6 × 18108
6 × 19114
6 × 20120

To understand the concept of finding multiples, let us take a few more examples.

Important Notes:

Every number is the smallest multiple of itself.All the multiples of 6 are multiples of both 2 and 3. 24 is a multiple of 2 and 3.A multiple can be the common multiple of two or more numbers.Example: 100 is the common multiple of 2, 4, 5, 10, 20, 25, and 50.

Example 1

Andrea decides to make bracelets one by one in such a way that there are 6 beads in the first bracelet, 12 in the second, 18 in the third, and so on. How many beads would she need to make the 45th bracelet?

Solution

In the 4th bracelet, Andrea needs 4×6 = 24 beads

In the 8th bracelet, she needs 8×6 = 48 beads.

Hence for nth bracelet, she needs n×6 beads.

Here she looks for the 45th bracelet.

Thus, Andrea needs 45×6 = 270 beads.

Example 2

Mike is playing a video game. For every jump over the obstacle, he collects 6 coins. He wants to know how many coins he would have collected if he crosses 112 such jumps. Can you help him to calculate the score?

Solution

In one jump, Mike gets 6 coins.

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In 112 jumps, he would have collected 112×6 = 672 coins.

Example 3

Mia gets a score of 6 points from 8 judges at each level. What will be her score at the end of the 66th level?